This new pH of millimolar HCl try ………… Question 75. (a) 1 (b) step three (c) dos (d) cuatro Answer: (b) step three Provider: pH = – diary [H + ] [H + ] = 10 -3 pH = journal step 1 – diary [H + ] = log 1 – journal 10 -step three […]
This new pH of millimolar HCl try …………
